S.Turner's CAS-CERN Accelerator School - Advanced Accelerator Physics PDF

By S.Turner

CERN (Series), 95-06. 2 volumes : illustrations ; 30 cm. ISBN vol. 1: 9290830786 ISBN vol. 2: 9290830794

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83. Picture the Problem: The swimmers fall straight down from the bridge into the water. Strategy: The initial velocities of the swimmers are zero because they step off the bridge rather than jump up or dive downward. 81 m/s2. Set x0 = 0 and let downward be the positive direction for simplicity. The known acceleration can be used to find velocity as a function of time for part (b). Finally, the same equation of motion for part (a) can be solved for time in order to answer part (c). 5 ) Solution: 1.

2 s ) = 24 m 2. 2 s ) = 22 m/s = 48 mi/h! 3. 75 m ) 2 2 Insight: Increasing the stopping distance will decrease the stopping acceleration. We will return to this idea when we discuss impulse and momentum in Chapter 9. Copyright © 2010 Pearson Education, Inc. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher. 2 – 33 James S. Walker, Physics, 4th Edition Chapter 2: One-Dimensional Kinematics 103.

Once the time is known, the displacement and velocity of the bicyclist can be determined from equations 2-10 and 2-7, respectively. xfriend = xbicyclist Solution: 1. (a) Set the two equations of motion equal to each other. For the friend, use equation 2-8 with x0 = 0 and for the bicyclist, use equation 2-11 with x0 = 0 and v0 = 0 : v f t = 0 + 0 + 12 ab ( t − 2 ) 2. 92t + 4 3. 64 s 4. 0 s, the time at which the bicyclist began pursuing his friend. 3 s after his friend passes him. 5. 3 s ) = 22 m 6.

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CAS-CERN Accelerator School - Advanced Accelerator Physics (VOL 2) by S.Turner


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